p34_087 - 87. E B = 0 S , where E = E k and S = S ( One can...

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87. ~ E × ~ B = µ 0 ~ S ,where ~ E = E ˆ kand ~ S = S ( ˆ j). One can verify easily that since ˆ k × ( ˆ i) = ˆ j, ~ B has to be in the negative
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