p35_004 - 4 In each case there is an object and its...

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Unformatted text preview: 4. In each case there is an object and its “first” image in the mirror closest to it (this image is the same distance behind the mirror as the object is in front of it and might be referred to as the object’s “twin”). The rest of the “figuring” consists of drawing perpendiculars from these (or imagining doing so) to the mirror-planes and constructing further images. (a) For θ = 45 ◦ , we have two images in the second mirror caused by the object and its “first” image, and from these one can construct two new images I and I behind the first mirror plane. Extending the second mirror plane, we can find two further images of I and I which are on equal sides of the extension of the first mirror plane. This circumstance implies there are no further images, since these final images are each other’s “twins.” We show this construction in the figure below. Summarizing, we find 1 + 2 + 2 + 2 = 7 images in this case....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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