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Unformatted text preview: 8. We apply the law of refraction, assuming all angles are in radians: sin sin = n w n air , which in our case reduces to /n w (since both and are small, and n air 1). We refer to our figure, below. The object O is a vertical distance h 1 above the water, and the water surface is a vertical distance h 2 above the mirror. We are looking for a distance d (treated as a positive number) below the mirror where the image I of the object is formed. In the triangle OAB  AB  = h 1 tan h 1 , and in the triangle CBD  BC  = 2 h 2 tan 2 h 2 2 h 2 n w . Finally, in the triangle ACI, we have  AI  = d + h 2 . Therefore, d =  AI  h 2 =  AC  tan h 2  AB  +  BC  h 2 = h 1 + 2 h 2 n w 1 h 2 = h 1 + 2 h 2 n w h 2 = 250 cm + 2(200 cm) 1 . 33 200 cm = 351 cm . .....................................................................................................................................................................................................
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 Fall '08
 SPRUNGER
 Physics

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