p35_016 - 20 mm layer of water where this “object”...

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16. First, we note that – relative to the water – the index of refraction of the carbon tetrachloride should be thought of as n =1 . 46 / 1 . 33 = 1 . 1 (this notation is chosen to be consistent with problem 15). Now, if the observer were in the water, directly above the 40 mm deep carbon tetrachloride layer, then the apparent depth of the penny as measured below the surface of the carbon tetrachloride is d a =40mm / 1 . 1= 36 . 4 mm. This “apparent penny” serves as an “object” for the rays propagating upward through the
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Unformatted text preview: 20 mm layer of water, where this “object” should be thought of as being 20 mm + 36 . 4 mm = 56 . 4 mm from the top surface. Using the result of problem 15 again, we ±nd the perceived location of the penny, for a person at the normal viewing position above the water, to be 56 . 4 mm / 1 . 33 = 42 mm below the water surface....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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