Unformatted text preview: 24. (a) Since this is a converging lens (“C”) then f > 0, so we should put a plus sign in front of the “10” value given for the focal length. There is not enough information to determine r 1 and r 2 . Eq. 359 gives i = 1 1 f − 1 p = 1 1 10 − 1 20 = +20 cm . There is insuﬃcient information for the determination of n . From Eq. 356, m = − 20 / 20 = − 1 . 0. The image is real (since i > 0) and inverted (since m < 0). The ray diagram would be similar to Fig. 3514(a) in the textbook. (b) Since f > 0, this is a converging lens (“C”). There is not enough information to determine r 1 and r 2 . Eq. 359 gives i = 1 1 f − 1 p = 1 1 10 − 1 5 = − 10 cm . There is insuﬃcient information for the determination of n . From Eq. 356, m = − ( − 10) / 5 = +2 . 0. The image is virtual (since i < 0) and upright (since m > 0). The ray diagram would be similar to Fig. 3514(b) in the textbook....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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