This preview shows page 1. Sign up to view the full content.
Unformatted text preview: x , we set dx/dp = 0 and solve for p . Since dx dp = p ( p − 2 f ) ( p − f ) 2 , the result is p = 2 f . The minimum distance is x min = p 2 p − f = (2 f ) 2 2 f − f = 4 f . This is a minimum, rather than a maximum, since the image distance i becomes large without bound as the object approaches the focal point....
View
Full
Document
This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

Click to edit the document details