p35_027 - ¶ − 1 = − 30 cm . Thus, the image formed by...

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27. Without the diverging lens (lens 2), the real image formed by the converging lens (lens 1) is located at a distance i 1 = µ 1 f 1 1 p 1 1 = µ 1 20 cm 1 40 cm 1 =40cm to the right of lens 1. This image now serves as an object for lens 2, with p 2 = (40 cm 10 cm) = 30 cm . So i 2 = µ 1 f 2 1 p 2 1 = µ 1 15 cm 1 30 cm
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Unformatted text preview: ¶ − 1 = − 30 cm . Thus, the image formed by lens 2 is located 30 cm to the left of lens 2. It is virtual (since i 2 < 0). The magniFcation is m = ( − i 1 /p 1 ) × ( − i 2 /p 2 ) = +1, so the image has the same size and orientation as the object....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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