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Unformatted text preview: 28. (a) For the image formed by the ﬁrst lens
1
1
−
f1
p1 i1 = −1 = 1
1
−
10 cm 20 cm −1 = 20 cm . For the subsequent image formed by the second lens p2 = 30 cm − 20 cm = 10 cm, so
i2 = 1
1
−
f2
p2 −1 = 1
1
−
12.5 cm 10 cm −1 = −50 cm . Thus, the ﬁnal image is 50 cm to the left of the second lens, which means that it coincides with the
object. The magniﬁcation is
m= i1
p1 i2
p2 = 20 cm
20 cm −50 cm
10 cm = −5.0 , which means that the ﬁnal image is ﬁve times larger than the original object.
(b) The ray diagram would be very similar to Fig. 3517 in the textbook, except that the ﬁnal image
would be directly underneath the original object.
(c) and (d) It is virtual and inverted. ...
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 Fall '08
 SPRUNGER
 Physics

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