p35_028 - 28. (a) For the image formed by the first lens 1...

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Unformatted text preview: 28. (a) For the image formed by the first lens 1 1 − f1 p1 i1 = −1 = 1 1 − 10 cm 20 cm −1 = 20 cm . For the subsequent image formed by the second lens p2 = 30 cm − 20 cm = 10 cm, so i2 = 1 1 − f2 p2 −1 = 1 1 − 12.5 cm 10 cm −1 = −50 cm . Thus, the final image is 50 cm to the left of the second lens, which means that it coincides with the object. The magnification is m= i1 p1 i2 p2 = 20 cm 20 cm −50 cm 10 cm = −5.0 , which means that the final image is five times larger than the original object. (b) The ray diagram would be very similar to Fig. 35-17 in the textbook, except that the final image would be directly underneath the original object. (c) and (d) It is virtual and inverted. ...
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