Unformatted text preview: 1 f = ( n âˆ’ 1) Âµ 1 r 1 âˆ’ 1 r 2 Â¶ where r 1 and r 2 are the radii of curvature of the two surfaces of the lens and n is the index of refraction of the lens material. Â±or the lens pictured in Â±ig. 3534, r 1 and r 2 have about the same magnitude, r 1 is positive, and r 2 is negative. Since the focal length decreases, the combination (1 /r 1 ) âˆ’ (1 /r 2 ) must increase. This can be accomplished by decreasing the magnitudes of both radii....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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