p35_043 - f < 0; in fact, f = 2 . 00 cm. Substituting i...

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43. (a) (b) and (c) Since m =+0 . 250, we have i = 0 . 25 p which indicates that the image is virtual (as well as being diminished in size). We conclude from this that the mirror is convex and that
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Unformatted text preview: f < 0; in fact, f = 2 . 00 cm. Substituting i = p/ 4 into Eq. 35-4 produces 1 p 4 p = 3 p = 1 f Therefore, we Fnd p = 6 . 00 cm and i = 1 . 50 cm....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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