p35_047 - 47. (a) (b) and (c) Our first step is to form...

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Unformatted text preview: 47. (a) (b) and (c) Our first step is to form the image from the first lens. With p1 = 4 cm and f1 = −4 cm, Eq. 35-9 leads to 1 1 1 + = =⇒ i1 = −2 cm . p1 i1 f1 The corresponding magnification is m1 = −i1 /p1 = 1/2. This image serves the role of “object” for the second lens, with p2 = 10 + 2 = 12 cm, and f2 = −4 cm. Now, Eq. 35-9 leads to 1 1 1 + = p2 i2 f2 =⇒ i2 = −3.00 cm with a corresponding magnification of m2 = −i2 /p2 = 1/4, resulting in a net magnification of m = m1 m2 = 1/8. The fact that m is positive means that the orientation of the final image is the same as the (original) object. The fact that i2 is negative means that the final image is virtual. ...
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