p35_049 - 1 p − 10 3 p = − 7 3 p = 1 f Therefore we Fnd...

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49. Since 0 <m< 1, we conclude the lens is of the diverging type (so f = 40 cm). Thus, substituting i = 3 p/ 10 into Eq. 35-9 produces
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Unformatted text preview: 1 p − 10 3 p = − 7 3 p = 1 f . Therefore, we Fnd p = 93 . 3 cm and i = − 28 . 0 cm....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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