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Unformatted text preview: 50. (a) We use Eq. 358 (and Fig. 3510(b) is useful), with n1 = 1 (using the roundedoﬀ value for air) and
n2 = 1 . 5 .
1 1.5
1.5 − 1
+
=
p
i
r
Using the sign convention for r stated in the paragraph following Eq. 358 (so that r = +6.0 cm),
we obtain i = −90 cm for objects at p = 10 cm. Thus, the object and image are 80 cm apart.
(b) The image distance i is negative with increasing magnitude as p increases from very small values
to some value p0 at which point i → −∞. Since 1/(−∞) = 0, the above equation yields
1
1.5 − 1
=
p0
r =⇒ p0 = 2r. Thus, the range for producing virtual images is 0 < p ≤ 12 cm. ...
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 Fall '08
 SPRUNGER
 Physics

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