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Unformatted text preview: /p + 1 /i = 1 /f yields i = − . 15 m, which means the image is 15 cm from the front surface, appearing to be inside the sphere. (b) and (c) The lateral magniFcation is m = − i/p which yields m = 0 . 15. Therefore, the image distance is (0 . 15)(2 . 0 m) = 0 . 30 m; that this is a positive value implies the image is erect (upright)....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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