p35_056 - p = 4(12) / 3 = 16 cm. (c) With m = 1 / 3, we...

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56. (a) The mirror has focal length f =12cm . W ith m =+3 ,wehave i = 3 p . We substitute this into Eq. 35-4: 1 p + 1 i = 1 f 1 p + 1 3 p = 1 12 2 3 p = 1 12 with the unit cm understood. Consequently, we Fnd p = 2(12) / 3=8 . 0cm . (b) With m = 3, we have i =+3 p , which we substitute into Eq. 35-4: 1 p + 1 i = 1 f 1 p + 1 3 p = 1 12 4 3 p
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Unformatted text preview: p = 4(12) / 3 = 16 cm. (c) With m = 1 / 3, we have i = p/ 3. Thus, Eq. 35-4 leads to 1 p + 1 i = 1 f 1 p + 3 p = 1 12 4 p = 1 12 with the unit cm understood. Consequently, we Fnd p = 4(12) = 48 cm....
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