p36_008 - 8. (a) Eq. 36-11 (in absolute value) yields (8.50...

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8. (a) Eq. 36-11 (in absolute value) yields L λ | n 2 n 1 | = (8 . 50 × 10 6 m) 500 × 10 9 m (1 . 60 1 . 50) = 1 . 70 . (b) Similarly, L λ | n 2 n 1 | = (8 . 50 × 10 6 m) 500 × 10 9 m (1 . 72 1 . 62) = 1 . 70 . (c) In this case, we obtain L λ | n 2 n 1 | = (3 . 25 × 10 6 m) 500 × 10 9 m (1 . 79 1 . 59) = 1 . 30 . (d) Since their phase diferences were identical, the brightness should be the same For (a) and (b). Now,
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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