p36_009 - these phase diFerences and letting all lengths be...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
9. (a) We choose a horizontal x axis with its origin at the left edge of the plastic. Between x =0and x = L 2 the phase diFerence is that given by Eq. 36-11 (with L in that equation replaced with L 2 ). Between x = L 2 and x = L 1 the phase diFerence is given by an expression similar to Eq. 36-11 but with L replaced with L 1 L 2 and n 2 replaced with 1 (since the top ray in ±ig. 36-28 is now traveling through air, which has index of refraction approximately equal to 1). Thus, combining
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: these phase diFerences and letting all lengths be in µ m (so λ = 0 . 600), we have L 2 λ ( n 2 − n 1 ) + L 1 − L 2 λ (1 − n 1 ) = 3 . 50 . 600 (1 . 60 − 1 . 40) + 4 . 00 − 3 . 50 . 600 (1 − 1 . 40) = 0 . 833 . (b) Since the answer in part (a) is closer to an integer than to a half-integer, then the interference is more nearly constructive than destructive....
View Full Document

Ask a homework question - tutors are online