p36_023 - 23. The phasor diagram is shown below. Here E1 =...

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Unformatted text preview: 23. The phasor diagram is shown below. Here E1 = 1.00, E2 = 2.00, and φ = 60◦ . The resultant amplitude Em is given by the trigonometric law of cosines: 2 2 2 Em = E1 + E2 − 2E1 E2 cos(180◦ − φ) . Thus, Em = .... .. .. ...... . .... . .. .. ... .. ........ . ........ .. .... .. .... . .. .... . .. ... . . .. .... .. .... ... 2 ... .. . .. . ... . ... .. . .. ... ... .. ... . .. ... . . ... .. . ... .. ... ... . .. .. . ... . ... . m .. .. ... ... . .. . .. . . .. .. .. ..... ..... .. .. .. .. . . . .. .. . . . .. .. . 1 .. .. . .. .. .. . . .. . ... ... . E E φ E (1.00)2 + (2.00)2 − 2(1.00)(2.00) cos 120◦ = 2.65 . ...
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