p36_025 - + 5 . 0 sin( 45 ) = 4 . so that y R = q y 2 h + y...

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25. In adding these with the phasor method (as opposed to, say, trig identities), we mayse t t =0( see Sample Problem 36-3) and add them as vectors: y h =1 0 c o s 0 + 15 cos 30 +5 . 0cos( 45 )=26 . 5 y
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Unformatted text preview: + 5 . 0 sin( 45 ) = 4 . so that y R = q y 2 h + y 2 v = 26 . 8 = tan 1 y v y h = 8 . 5 . Thus, y = y 1 + y 2 + y 3 = y R sin( t + ) = 26 . 8 sin( t + 8 . 5 )....
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