P36_035 - 35 Light reflected from the front surface of the coating suffers a phase change of π rad while light reflected from the back surface

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Unformatted text preview: 35. Light reflected from the front surface of the coating suffers a phase change of π rad while light reflected from the back surface does not change phase. If L is the thickness of the coating, light reflected from the back surface travels a distance 2L farther than light reflected from the front surface. The difference in phase of the two waves is 2L(2π/λc ) − π , where λc is the wavelength in the coating. If λ is the wavelength in vacuum, then λc = λ/n, where n is the index of refraction of the coating. Thus, the phase difference is 2nL(2π/λ) − π . For fully constructive interference, this should be a multiple of 2π . We solve 2nL 2π λ − π = 2mπ for L. Here m is an integer. The solution is L= (2m + 1)λ . 4n To find the smallest coating thickness, we take m = 0. Then, L= λ 560 × 10−9 m = = 7.00 × 10−8 m . 4n 4(2.00) ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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