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Unformatted text preview: 36. Let the thicknesses (which appear in Fig. 3631 as diﬀerent heights h) of the structure be h = kL, where
k is a pure number. In section (b), for example, k = 2. Using Eq. 3634, the condition for constructive
interference becomes
(m + 1/2)λ
where m = 0, 1, 2, . . .
2h = 2(kL) =
n2
which leads to
k= (m + 1/2)λ
(m + 1/2)(600 nm)
2m + 1
=
=
,
3 nm)
2 n2 L
2(1.50)(4.00 × 10
40 or 40k − 1 = 2m. This means that 40k − 1 would have to be an even integer. One can check that none of
1
the given values of k (1, 2, 1 , 3, 10 ) will satisfy this condition. Therefore, none of the sections provides
2
the right thickness for constructive interference. ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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