p36_054 - N = (2 L/ )( n 1). Therefore, L = N 2( n 1) =...

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54. According to Eq. 36-41, the number of fringes shifted (∆ N ) due to the insertion of the Flm of thickness L is ∆
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Unformatted text preview: N = (2 L/ )( n 1). Therefore, L = N 2( n 1) = (589 nm)(7 . 0) 2(1 . 40 1) = 5 . 2 m ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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