p36_055 - Let N be the number of fringes shifted. Then, 2 d...

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55. A shift of one fringe corresponds to a change in the optical path length of one wavelength. When the mirror moves a distance d the path length changes by 2 d since the light traverses the mirror arm twice.
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Unformatted text preview: Let N be the number of fringes shifted. Then, 2 d = N and = 2 d N = 2(0 . 233 10 3 m) 792 = 5 . 88 10 7 m = 588 nm ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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