p36_061 - / 2) = 3(600 nm) = 1 . 80 m . (b) We must now...

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61. (a) Every time one more destructive (constructive) fringe appears the increase in thickness of the air gap is λ/ 2. Now that there are 6 more destructive fringes in addition to the one at point A ,the thickness at B is t B =6(
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Unformatted text preview: / 2) = 3(600 nm) = 1 . 80 m . (b) We must now replace by = /n w . Since t B is unchanged t B = N ( / 2) = N ( / 2 n w ), or N = 2 t B n w = 2(3 ) n w = 6 n w = 6(1 . 33) = 8 ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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