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Unformatted text preview: 74. Using the relations of §36-7, we ﬁnd that the (vertical) change between the center of one dark band and
the next is
∆y = λ2 = 2.5 × 10−4 mm .
Thus, with the (horizontal) separation of dark bands given by ∆x = 1.2 mm, we have
θ ≈ tan θ = ∆y
= 2.08 × 10−4 rad .
∆x Converting this angle into degrees, we arrive at θ = 0.012◦ . ...
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- Fall '08