p36_076 - 76. (a) With = 0.5 m, Eq. 36-14 leads to = sin1...

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76. (a) With λ =0 . 5 µ m, Eq. 36-14 leads to θ = sin 1 (3)(0 . 5 µ m) 2 . 00 µ m =48 . 6 . (b) Decreasing the frequency means increasing the wavelength – which implies y increases. Qualita- tively, this is easily seen with Eq. 36-17. One should exercise caution in appealing to Eq. 36-17 here, due to the fact the small angle approximation is not justiFed in this problem. The new wavelength
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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