p36_077 - ± 1 2 wavelength into the previous result –...

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77. (a) Following Sample Problem 36-1, we have N 2 N 1 = L λ ( n 2 n 1 )=1 . 87 which represents a meaningful di±erence of 0 . 87 wavelength. (b) The result in part (a) is closer to 1 wavelength (constructive interference) than it is to 1 2 wavelength (destructive interference) so the latter choice applies. (c) This would insert a
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Unformatted text preview: ± 1 2 wavelength into the previous result – resulting in a meaningful di±erence (between the two rays) equal to 0 . 87 − . 50 = 0 . 37 wavelength, which is closer to the destructive interference condition. Thus, there is intermediate illumination but closer to darkness....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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