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Unformatted text preview: 81. We adapt the result of problem 21. Now, the phase diﬀerence in radians is
2πt
(n2 − n1 ) = 2mπ .
λ
The problem implies m = 5, so the thickness is
t= mλ
5(480 nm)
=
= 8.0 × 103 nm = 8.0 µm .
n2 − n1
1.7 − 1.4 ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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