Unformatted text preview: 83. (a) In this case, the ﬁlm has a smaller index material on one side (air) and a larger index material on
the other (glass), and we are dealing (in part (a)) with strongly transmitted light, so the condition
is given by Eq. 3635 (which would give dark reﬂection in this scenario)
L= λ
2 n2 m+ 1
2 = 110 nm for n2 = 1.25 and m = 0.
(b) Now, we are dealing with strongly reﬂected light, so the condition is given by Eq. 3634 (which
would give no transmission in this scenario)
L= mλ
= 220 nm
2 n2 for n2 = 1.25 and m = 1 (the m = 0 option is excluded in the problem statement). ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Light

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