Unformatted text preview: 83. (a) In this case, the ﬁlm has a smaller index material on one side (air) and a larger index material on
the other (glass), and we are dealing (in part (a)) with strongly transmitted light, so the condition
is given by Eq. 36-35 (which would give dark reﬂection in this scenario)
2 n2 m+ 1
2 = 110 nm for n2 = 1.25 and m = 0.
(b) Now, we are dealing with strongly reﬂected light, so the condition is given by Eq. 36-34 (which
would give no transmission in this scenario)
= 220 nm
2 n2 for n2 = 1.25 and m = 1 (the m = 0 option is excluded in the problem statement). ...
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