p36_085 - Eq. 36-17 and Eq. 36-18). Thus, with m = 1, y = 0...

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85. Using Eq. 36-16 with the small-angle approximation (illustrated in Sample Problem 36-2), we arrive at y = ( m + 1 2 ) λD d for the position of the ( m +1) th dark band (a simple way to get this is by averaging the expressions in
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Unformatted text preview: Eq. 36-17 and Eq. 36-18). Thus, with m = 1, y = 0 . 012 m and d = 800 , we Fnd D = 6 . 4 m....
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