Unformatted text preview: 86. (a) The path length diﬀerence between Rays 1 and 2 is 7d − 2d = 5d. For this to correspond to a
half-wavelength requires 5d = λ/2, so that d = 50.0 nm.
(b) The above requirement becomes 5d = λ/2n in the presence of the solution, with n = 1.38. Therefore,
d = 36.2 nm. ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
- Fall '08