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Unformatted text preview: 1. The condition for a minimum of a single-slit diﬀraction pattern is a sin θ = mλ where a is the slit width, λ is the wavelength, and m is an integer. The angle θ is measured from the forward direction, so for the situation described in the problem, it is 0.60◦ for m = 1. Thus a= mλ 633 × 10−9 m = 6.04 × 10−5 m . = sin θ sin 0.60◦ ...
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- Fall '08