p37_002 - 2(a θ = sin−1(1.50 cm/2.00 m = 0.430◦(b For...

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Unformatted text preview: 2. (a) θ = sin−1 (1.50 cm/2.00 m) = 0.430◦ . (b) For the mth diffraction minimum a sin θ = mλ. We solve for the slit width: a= mλ 2(441 nm) = 0.118 mm . = sin θ sin 0.430◦ ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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