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Unformatted text preview: 4. (a) We use Eq. 373 to calculate the separation between the ﬁrst (m1 = 1) and ﬁfth (m2 = 5) minima: ∆y = D∆ sin θ = D∆ Solving for the slit width, we obtain a= (b) For m = 1, sin θ = Dλ(m2 − m1 ) (400 mm)(550 × 10−6 mm)(5 − 1) = = 2.5 mm . ∆y 0.35 mm mλ (1)(550 × 10−6 mm) = = 2.2 × 10−4 . a 2.5 mm mλ a = Dλ Dλ ∆m = (m 2 − m 1 ) . a a The angle is θ = sin−1 (2.2 × 10−4 ) = 2.2 × 10−4 rad. ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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