p37_022 - 22. Since we are considering the diameter of the...

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Unformatted text preview: 22. Since we are considering the diameter of the central diffraction maximum, then we are working with twice the Rayleigh angle. Using notation similar to that in Sample Problem 37-6 (which is in the textbook supplement), we have 2(1.22λ/d) = D/L. Therefore, d=2 1.22λL (1.22)(500 × 10−9 m)(3.54 × 105 m) =2 = 0.047 m . D 9.1 m ...
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