p37_033 - 33. (a) d = 20.0 mm/6000 = 0.00333 mm = 3.33 m....

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33. (a) d =20 . 0mm / 6000 = 0 . 00333 mm = 3 . 33 µ m . (b) Let d sin θ = ( m =0 , ± 1 , ± 2 , ··· ). We fnd θ =0For m =0,and θ = sin 1 ( ± λ/d ) = sin 1 µ ± 0 . 589 µ m 3 . 30 µ m = ± 10 . 2 For m = ± 1. Similarly, we fnd ± 20 . 7 For m = ± 2, ± 32 . 2
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