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Unformatted text preview: 36. We use Eq. 37-22 for diﬀraction maxima: d sin θ = mλ. In our case, since the angle between the m = 1
and m = −1 maxima is 26◦ , the angle θ corresponding to m = 1 is θ = 26◦ /2 = 13◦ . We solve for the
= 2 . 4 µm .
sin 13◦ ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
- Fall '08