p37_038 - 38. (a) For the maximum with the greatest value...

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38. (a) For the maximum with the greatest value of m (= M )wehave = a sin θ<d ,so M<d/λ = 900 nm / 600 nm = 1 . 5, or M = 1. Thus three maxima can be seen, with m =0 , ± 1 . (b) From Eq. 37-25
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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