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38.
(a) For the maximum with the greatest value of
m
(=
M
)wehave
Mλ
=
a
sin
θ<d
,so
M<d/λ
=
900 nm
/
600 nm = 1
.
5, or
M
= 1. Thus three maxima can be seen, with
m
=0
,
±
1
.
(b) From Eq. 3725
∆
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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