This preview shows page 1. Sign up to view the full content.
40. We use Eq. 3722. For
m
=
±
1
λ
=
d
sin
θ
m
=
(1
.
73
µ
m) sin(
±
17
.
6
◦
)
±
1
= 523 nm
,
and for
m
=
±
2
λ
=
(1
.
73
µ
m) sin(
±
37
.
3
◦
)
±
2
= 524 nm
.
Similarly, we may compute the values of
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

Click to edit the document details