Unformatted text preview: 56. (a) For the ﬁrst beam 2d sin θ1 = λA and for the second one 2d sin θ2 = 3λB . The values of d and λA
can then be determined:
d=
(b) 3 λB
3(97 pm)
=
= 1.7 × 102 pm .
2 sin θ2
2 sin 60◦ λA = 2d sin θ1 = 2(1.7 × 102 pm)(sin 23◦ ) = 1.3 × 102 pm . ...
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 Fall '08
 SPRUNGER
 Physics, Sin

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