p37_056 - 56. (a) For the first beam 2d sin θ1 = λA and...

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Unformatted text preview: 56. (a) For the first beam 2d sin θ1 = λA and for the second one 2d sin θ2 = 3λB . The values of d and λA can then be determined: d= (b) 3 λB 3(97 pm) = = 1.7 × 102 pm . 2 sin θ2 2 sin 60◦ λA = 2d sin θ1 = 2(1.7 × 102 pm)(sin 23◦ ) = 1.3 × 102 pm . ...
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