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73. (a) Use of Eq. 3722 for the limitwavelengths (
λ
1
= 700 nm and
λ
2
= 550 nm) leads to the condition
m
1
λ
1
≥
m
2
λ
2
for
m
1
+1=
m
2
(the low end of a highorder spectrum is what is overlapping with the high end of
the nextlowerorder spectrum). Assuming equality in the above equation, we can solve for “
m
1
”
(realizing it might not be an integer) and obtain
m
1
≈
4 where we have rounded
up
. It is the fourth
order spectrum that is the lowestorder spectrum to overlap with the next higher spectrum.
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 Fall '08
 SPRUNGER
 Physics

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