73. (a) Use of Eq. 37-22 for the limit-wavelengths ( λ 1 = 700 nm and λ 2 = 550 nm) leads to the condition m 1 λ 1 ≥ m 2 λ 2 for m 1 +1= m 2 (the low end of a high-order spectrum is what is overlapping with the high end of the next-lower-order spectrum). Assuming equality in the above equation, we can solve for “ m 1 ” (realizing it might not be an integer) and obtain m 1 ≈ 4 where we have rounded up . It is the fourth order spectrum that is the lowest-order spectrum to overlap with the next higher spectrum.
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