p37_075 - = 500 nm). Since the angles are the same, then...

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75. As a slit is narrowed, the pattern spreads outward, so the question about “minimum width” suggests that we are looking at the lowest possible values of m (the label for the minimum produced by light λ = 600 nm) and m 0 (the label for the minimum produced by light
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Unformatted text preview: = 500 nm). Since the angles are the same, then Eq. 37-3 leads to m = m which leads to the choices m = 5 and m = 6. We Fnd the slit width from Eq. 37-3: a = m sin m which yields a = 3 . 0 mm....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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