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Unformatted text preview: 76. (a) We note that d = (76 × 106 nm)/40000 = 1900 nm. For the ﬁrst order maxima λ = d sin θ, which
leads to
λ
589 nm
θ = sin−1
= sin−1
= 18◦ .
d
1900 nm
Now, substituting m = d sin θ/λ into Eq. 3727 leads to D = tan θ/λ = tan 18◦ /589 nm = 5.5 ×
10−4 rad/nm = 0.032◦ /nm. Similarly for m = 2 and m = 3, we have θ = 38◦ and 68◦ , and the
corresponding values of dispersion are 0.076◦ /nm and 0.24◦ /nm, respectively.
(b) R = N m = 40000 m = 40000 (for m = 1); 80000 (for m = 2); and, 120, 000 (for m = 3). ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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