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Unformatted text preview: 87. The condition for a minimum in a singleslit diﬀraction pattern is given by Eq. 373, which we solve for
the wavelength:
a sin θ
(0.022 mm) sin 1.8◦
λ=
=
= 6.9 × 10−4 mm = 690 nm .
m
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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