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Unformatted text preview: t = d/v (see Eq. 3810), we wish to solve for v from Eq. 387. Our rst step is as follows: t = t p 1 ( v/c ) 2 d v = t p 1 ( v/c ) 2 23000 c y v = 30 y p 1 ( v/c ) 2 , at which point we can cancel the unit year and manipulate the equation to solve for the speed. After a couple of algebraic steps, we obtain v = c q 1 + ( 30 23000 ) 2 = 299792458 m / s 1 + 0 . 000017013 = 299792203 m / s which may also be expressed as v = 0 . 999 999 15 c . The discussion in Sample Problem 387 dealing with these sorts of values may prove helpful for those whose calculators do not yield this answer....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Special Relativity

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