p38_018 - 18. (a) In frame S , our coordinates are such...

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18. (a) In frame S , our coordinates are such that x 1 = +1200 m for the big flash, and x 2 = 1200 720 = 480 m for the small flash (which occurred later). Thus, ∆ x = x 2 x 1 = 720 m. If we set ∆ x 0 =0 in Eq. 38-24, we Fnd 0= γ (∆ x v t )= γ ( 720 m v (5 . 00 × 10 6 s) ) which yields v = 1 . 44 × 10 8 m/s. Therefore, frame S 0 must be moving in the x direction with a speed of 0 . 480 c . (b) Eq. 38-27 leads to t 0 = γ µ t v x c 2 = γ µ 5 . 00 × 10 6 s ( 1 . 44 × 10 8 m / s)( 720 m) (2 . 998 × 10 8 m / s) 2 which turns out to be positive (regardless of the speciFc value of
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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