p38_032 - W = m e c 2 1 p 1 2 1 ! = (511 keV)...

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32. (a) The work-kinetic energy theorem applies as well to Einsteinian physics as to Newtonian; the only diference is the speciFc ±ormula ±or kinetic energy. Thus, we use W =∆ K = m e c 2 ( γ 1) (Eq. 38- 49) and m e c 2 = 511 keV = 0 . 511 MeV (Table 38-3), and obtain
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Unformatted text preview: W = m e c 2 1 p 1 2 1 ! = (511 keV) " 1 p 1 (0 . 50) 2 1 # = 79 keV . (b) W = (0 . 511 MeV) 1 p 1 (0 . 990) 2 1 ! = 3 . 11 MeV . (c) W = (0 . 511 MeV) 1 p 1 (0 . 9990) 2 1 ! = 10 . 9 MeV ....
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