p38_034 - 34. From Eq. 38-49, = (K/mc2 ) + 1, and from Eq....

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
34. From Eq. 38-49, γ =( K/mc 2 ) + 1, and from Eq. 38-8, the speed parameter is β = p 1 (1 ) 2 . (a) Table 38-3 gives m e c 2 = 511 keV = 0 . 511 MeV, so the Lorentz factor is γ = 10 . 0MeV 0 . 511 MeV +1=20 . 57 , and the speed parameter is β = s 1 1 (20 . 57) 2 =0 . 9988 . (b) Table 38-3 gives m p c 2 = 938 MeV, so the Lorentz factor is γ =1+10 . 0MeV / 938 MeV = 1 . 01, and the speed parameter is β = r 1 1 1 . 01 2 =0 . 145 . (c) If we refer to the data shown in problem 36, we ±nd m α =4 . 0026 u, which (using Eq. 38-43) implies
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online