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35. From Eq. 3849,
γ
= (
K/mc
2
) + 1, and from Eq. 388, the speed parameter is
β
=
p
1
−
(1
/γ
)
2
.T
ab
l
e
383 gives
m
e
c
2
= 511 keV = 0
.
511 MeV, so the Lorentz factor is
γ
=
100 MeV
0
.
511 MeV
+ 1 = 197
,
and the speed parameter is
β
=
s
1
−
1
(197)
2
=0
.
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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