p38_035 - 35. From Eq. 38-49, = (K/mc2 ) + 1, and from Eq....

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35. From Eq. 38-49, γ = ( K/mc 2 ) + 1, and from Eq. 38-8, the speed parameter is β = p 1 (1 ) 2 .T ab l e 38-3 gives m e c 2 = 511 keV = 0 . 511 MeV, so the Lorentz factor is γ = 100 MeV 0 . 511 MeV + 1 = 197 , and the speed parameter is β = s 1 1 (197) 2 =0 .
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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