p38_038 - . 19) 2 1 p 1 (0 . 18) 2 ! = 0 . 996 keV . (b)...

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38. (a) The work-kinetic energy theorem applies as well to Einsteinian physics as to Newtonian; the only diference is the speciFc ±ormula ±or kinetic energy. Thus, we use W =∆ K where K = m e c 2 ( γ 1) (Eq. 38-49), and m e c 2 = 511 keV = 0 . 511 MeV (Table 38-3). Noting that ∆ K = m e c 2 ( γ f γ i ), we obtain W = m e c 2 1 q 1 β 2 f 1 p 1 β 2 i = (511 keV) Ã 1 p 1 (0
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Unformatted text preview: . 19) 2 1 p 1 (0 . 18) 2 ! = 0 . 996 keV . (b) Similarly, W = (511 keV) 1 p 1 (0 . 99) 2 1 p 1 (0 . 98) 2 ! = 1055 keV . We see the dramatic increase in diculty in trying to accelerate a particle when its initial speed is very close to the speed o light....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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